0=u^2+14u+18

Solution for 0=u^2+14u+18 equation:

0=u^2+14u+18

We move all terms to the left:

0-(u^2+14u+18)=0

We add all the numbers together, and all the variables

-(u^2+14u+18)=0

We get rid of parentheses

-u^2-14u-18=0

We add all the numbers together, and all the variables

-1u^2-14u-18=0

a = -1; b = -14; c = -18;
Δ = b2-4ac
Δ = -142-4·(-1)·(-18)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{31}}{2*-1}=\frac{14-2\sqrt{31}}{-2}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{31}}{2*-1}=\frac{14+2\sqrt{31}}{-2}
$